#### Answer

$E = 0.16~V/m$

#### Work Step by Step

We can find the required electric field strength:
$E = \frac{I}{\sigma~A}$
$E = \frac{I}{\sigma~\pi~r^2}$
$E = \frac{5.0~A}{(1.0\times 10^7~S/m)~(\pi)~(1.0\times 10^{-3}~m)^2}$
$E = 0.16~V/m$

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Published by
Pearson

ISBN 10:
0133942651

ISBN 13:
978-0-13394-265-1

$E = 0.16~V/m$

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