# Line slope calculator 9x-5y=31

**Straight line given by points A[4; 1] and B[9; 10]**

## Calculation:

**Slope-intercept form of line:**y = 1.8x-6.2

**Canonical form of the line equation:**9x-5y-31 = 0

**Parametric form of the line equation:**

x = 5t+4

y = 9t+1 ; t ∈ R

**Slope:**m = 1.8

**Slope angle of line: φ =**60°56'43″ = 1.0637 rad

**X intercept:**x

_{0}= 3.4444

**Y intercept:**y

_{0}= q = -6.2

**Distance line from the origin:**d

_{0}= 3.011

**The length of the segment AB: |AB| =**10.2956

**Vector: AB =**(5; 9)

**Normal vector: n =**(9; -5)

**Midpoint of the segment AB: M =**[6.5; 5.5]

**Perpendicular Bisector equation:**5x+9y-82 = 0

**Vector OA = (4; 1) ; |OA| = 4.1231**

**Vector OB = (9; 10) ; |OB| = 13.4536**

**Scalar product OA .OB = 46**

**Angle ∠ AOB = 33°58'36″ = 0.593 rad**